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4 years ago

Jillian said /25 is irrational because it is a square root. Why is she incorrect?

2 answers:

6 0

Hi there,

Jillian made a wrong assumption because even though this is a square root, this is a perfect square root simplifying to 5. And 5 is not an irrational number.

Hope this helps!

saveliy_v [14]4 years ago

5 0

Jillian is incorrect because this is a square root simplifying to 5, and as mentioned 5 isn't an irrational number.

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3 years ago

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PLEASE HELP.! Solve for k. 2 = k/3 k = ?

borishaifa [10]

Answer:

Step-by-step explanation:

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3 years ago

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A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

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Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

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The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$

The standard deviation of this sampling distribution of sample proportion is:

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So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion z-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

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Hₐ: The proportion of women is more than men who exercise regularly, i.e. $p_{X}-p_{Y}$ .

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