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nikdorinn [45]
2 years ago
12

What is the square root of -^54/6+2/3

Mathematics
1 answer:
Kay [80]2 years ago
8 0
My guess is 3.109126351029605. I am not 100% sure its the correct answer you are looking for. Good luck!
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A ball is kicked off of the roof of a building. The path the ball travels is modeled by the equation f(x)= -x^2 + 6x+ 16, where
damaskus [11]

Answer:

This question is a rather easy one which can be answered by simply solving the embedded quadratic equation.

f(x) = -x^{2} + 6x + 16

To make our solving easier, what we do is multiply the whole equation by -1. By so doing, we make "x" positive. Then, we have

f(x) = x^{2} - 6x - 16

Solving this equation quadratically, we have

x^{2} + 2x - 8x - 16 = and when we factorize this expression, we have

x(x + 2) -8(x + 2) =

(x - 8) (x + 2) = 0

x - 8 = 0, x + 2 = 0

x = 8, or  x = -2

Since distance can not be in negative(minus), we then have our x to be 8 meters.

Another example on factorization can be seen here  brainly.com/question/13813750

3 0
3 years ago
What is the solution to the equation Negative 4 (2 x + 3) = 2 x + 6 minus (8 x + 2)?
shtirl [24]

Answer:

x = –8

Step-by-step explanation:

6 0
2 years ago
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Robin bought 4 feet of string.She uses 10 inches to make each necklace and 6 inches to make each bracelet. If she makes 4 bracel
Nataly [62]
She can make 2 necklaces with 4 inches remaining of string. 
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Which sequences of transformations confirm the congruence of shape II and shape I?
defon
The answer is -1 and 12
3 0
3 years ago
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Does each function describe exponential growth or decay?
zhannawk [14.2K]

Hey Jinx :)

------------------------------------------------

Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.

y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH

y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY

y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH

y = 200(0.73)^t → (Rate is between 0 and 1) DECAY

y = 4(1/4)^t → (Rate is between 0 and 1) DECAY

------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
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