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shtirl [24]
3 years ago
13

Disk scheduling algorithms in operating systems consider only seek distances, because Select one: a. modern disks do not disclos

e the physical location of logical blocks. b. the operating systems may have other constraints such as writes may be more urgent than reads. c. rotational latency is insignificant compared to the average seek time. d. it is difficult to optimize seek time in disk hardware.
Computers and Technology
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

a. modern disks do not disclose the physical location of logical blocks.

Explanation:

In modern disks, the disk scheduling algorithms are built in the disk drive. It is difficult for operating system to schedule for improved rotational latency. All scheduling algorithms are forced to behave the same because operating system may have constraints. Disks are usually accessed in physical blocks. Modern disks put more electronic controls on the disk.

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How many types of operating systems do we have as from 2010 till date​
RideAnS [48]

Answer:

2010 Census Apportionment Results. December 2010. Apportionment is the process of dividing the 435 memberships, or seats, in the U.S. House of Representatives among the 50 states. At the conclusion …

Explanation:

4 0
3 years ago
Design a program that asks the user to enter a store’s sales for each day of the week. The amounts should be stored in an array.
sdas [7]

Answer:

Program given below

Explanation:

Total Sales

Assign the values of the variable as “Enter the store sales for Sunday” in Sun

Assign the values of the variable as “Enter the store sales for Monday” in Mon

Assign the values of the variable as “Enter the store sales for Tuesday” in Tue

Assign the values of the variable as “Enter the store sales for Wednesday” in Wed

Assign the values of the variable as “Enter the store sales for Thursday” in Thu

Assign the values of the variable as “Enter the store sales for Friday” in Fri

Assign the values of the variable as “Enter the store sales for Saturday” in Sat

Assign the values for the variable in array as [Sun, Mon, Tue, Wed, Thu, Fri, Sat]

Initialize tot = 0

Use the loop for calculating the total sales for the week,

for total_sales in store_sales:

    tot += total_sales

then display the result as,    

print "\n Total week sales = %2.f " %tot

sun = int(input("\n Enter the store sales for Sunday: "))

mon = int(input("\n Enter the store sales for Monday: "))

tue = int(input("\n Enter the store sales for Tuesday: "))

wed = int(input("\n Enter the store sales for Wednesday: "))

thu = int(input("\n Enter the store sales for Thursday: "))

fri = int(input("\n Enter the store sales for Friday: "))

sat = int(input("\n Enter the store sales for Saturday: "))

store_sales = [sun, mon, tue, wed, thu, fri, sat]

tot = 0

for store_sale in store_sales:

tot += store_sale

print "\n Total Week Sales: %2.f" %tot

We will have the following output:

<u>OUTPUT </u>

<u> </u>Enter the store sales for Sunday: 45

Enter the store sales for Monday: 56

Enter the store sales for Tuesday: 89

Enter the store sales for Wednesday:78

Enter the store sales for Thursday: 45

Enter the store sales for Friday: 12

Enter the store sales for Saturday: 23

Total Week Sales: 348

8 0
3 years ago
Create the following matrix M: 1 7 13 19 25 ?-3 9 15 21 27 5 11 17 2329By writing one command and using the colon to address ran
zimovet [89]

Answer:

Matlab code is:

>> M=reshape(1:2:29, 3,5)

>> \%  (a)

>> Va=M(3,:)

>> \% (b)

>> Vb=M(:,4)

>> \% (c)

>> Vc=[M(2,:) M(:,3)']

Explanation:

>>\% \ Making\ the\ Matrix\ With\ required\ terms\ 1\ to\ 29\ with\ spaces\ of\ 5\ in\ three\ rows

>> M=reshape(1:2:29, 3,5)

M =

              1   7  13  19  25

              3  9  15  21  27

              5  11  17  23  29

>> \%  (a)

>>\%\ Slicing\ M\ \ from\ third\ row\ till\ end

>> Va=M(3,:)

Va =\\\ 5\ 11\ 17\ 23\ 29

>> \% (b)

>>\% \ Slicing\ the\4th\ column\ of\  M\ matrix\

>> Vb=M(:,4)

Vb =\\ 19\\ 21\\ 23\\

>> \% (c)

>>\% \ slicing\ the\ 2nd\ row\ and\ 3rd\ column\ of\ M\ Matrix\ and\ combining\ them\ to\ make\ a\ row\ matrix

>> Vc=[M(2,:) M(:,3)']

Vc =\\ 3\ 9\ 15\ 21\ 27\ 13\ 15\ 17

>>

The code is tested and is correct. If you put a semi colon ' ; ' at the end of every statement then your answer will be calculated but matlab doesn't show it until you ask i.e. typing the variable (Va, Vb, Vc )and press enter.

6 0
3 years ago
The next four octal numbers after 36 is:________.
Papessa [141]

Answer: b. 37, 40, 41, 42

Explanation:

The next four octal numbers after 36 is 37, 40, 41, 42.

The octal numeral system, which is also referred to as "oct" for short, is simply base-8 number system.

It is a number system whereby only digits from 0 to 7 are used and there are no letters or numbers that are above 8 that are used.

In this case, after 36, the next number will be 37 after which we go to 40 as we can't write 38 in the octal system. Therefore, the next four octal numbers after 36 is 37, 40, 41, 42.

7 0
4 years ago
Please help ASAP, will mark brainliest!
sp2606 [1]

Answer:

Stick to concrete nouns

Explanation:

The best technique to improve the web search result is that search with the help of keywords. These keywords help in searching the required results from search engines.

The keywords are actually nouns. Noun is name of object, place or person. So by using nouns we can search out required results.

For example

If we want to search about some persons bibliography, we use his name in our search. His name is an example of noun.

3 0
3 years ago
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