Answer:
--- True
--- False
--- True
Explanation:
Required
Determine if the statements are true or not.

To do this, we convert DE from base 16 to base 10 using product rule.
So, we have:

In hexadecimal.

So, we have:


Hence:
(a) is true

First, convert D7 to base 10 using product rule


So, we have:


Next convert 215 to base 2, using division rule








Write the remainders from bottom to top.

<em>Hence (b) is false</em>

Convert 13 to base 10 using product rule


Hence; (c) is true
Answer:
Check the explanation
Explanation:
#include <bits/stdc++.h>
using namespace std;
class Rectangle{
public:
int length;
int breadth;
Rectangle(int l,int b){
length = l;
breadth = b;
}
int area(){
return length*breadth;
}
int perimeter(){
return 2*(length+breadth);
}
bool equals(Rectangle* r){
// They have the exact same length and width.
if (r->length == length && r->breadth == breadth)
return true;
// They have the same area
if (r->area() == area())
return true;
// They have the same perimeter
if (r->perimeter() == perimeter())
return true;
// They have the same shape-that is, they are similar.
if (r->length/length == r->breadth/breadth)
return true;
return false;
}
};
int main(){
Rectangle *r_1 = new Rectangle(6,3);
Rectangle *r_2 = new Rectangle(3,6);
cout << r_1->equals(r_2) << endl;
return 0;
}
Answer:
log base 3a= -0.631.log a/3 base 3
Now, -log m= log 1/m
hence,
log base 3a= 0.631.log 3/a base 3
log base 3a/log 3/a base 3 =0.631
log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)
log base 3 3=0.631
Hence, answer is log base 3 3=0.631
Explanation:
Please check the answer section.
Answer:
True
Explanation: A qualifier is a term used in IT(information technology) and computer software. It is used to differentiate/ identify and select different sets of objects that are located at the far ends of a qualifier association.
A qualifier is usually used to identify an object from a set of closely related and similar objects, they are usually small boxes possibly with a rectangular shape.
Answer: False
Explanation:
This means that the mappings between the two schemas may be specified in either one of these languages.In most relational DBMSs today, there is no specific language that performs the role of SDL. Instead, the internal schema is specified by a combination of functions, parameters, and specifications related to storage. These permit the DBA staff to control indexing choices and mapping of data to storage