Answer:
I'd say that is an "occupancy problem".
I ran a spreadsheet simulation of that and I'd say the probability is approximately .13
Those problems are rather complex to solve. What I think you would have to do is calculate the probability of
A) ZERO sixes appearing in 4 rolls.
B) exactly 1 six appears in 4 rolls.
C) exactly 2 sixes appear in 4 rolls.
D) exactly 3 sixes appear in 4 rolls. and
E) exactly 4 sixes appear in 4 rolls.
4 rolls of a die can produce 6^4 or 1,296 combinations.
A) is rather easy to calculate: The probability of NOT rolling a six in one roll is 5/6. In 4 rolls it would be (5/6)^4 = 0.4822530864
E) is fairly easy to calculate: The probability of rolling one six is (1/6). The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049
Then we need to:
D) calculate how many ways can we place 3 objects into 4 bins
C) calculate how many ways can we place 2 objects into 4 bins
B) calculate how many ways can we place 1 objects into 4 bins
I don't know how to calculate D C and B
Step-by-step explanation:
Answer:
Step-by-step explanation:
So, we have the graph y=f(x).
And we want to find:
Remember that the inverse of a function is simply the x-values and y-values swapped. To see this, let's let our inverse equal y:
This means that we have the point:
So, to find our solution, we will swap the x- and y-coordinates. This gives us:
So, simply need to find the x-coordinate such that y is 0.
From our graph, we can see the point (6,0). In other words:
So:
And we're done!
Answer:
It is the last answer.
Step-by-step explanation:
If you graph this, there will be no point more negative than (-4/3, -5).
This means the x and y values must be greater than or equal to these values, as the fourth answer will show.
