Answer:
The mixture contains 47 lb of Colombian Supreme and 3 lb of Mocha Java.
Step-by-step explanation:
We are given the following in the question:
Let x be the amount of Colombian supreme and y be the amount of Mocha java in the mixture.
Total amount of mixture = 50 lb
Thus, we can write the equation:
![x + y =50](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D50)
Total unit cost of mixture = $5.93/lb
Cost of Colombian Supreme = $4.99/lb
Cost of Mocha Java = $5.99/lb
Thus, we can write the equation:
![\dfrac{4.99x+5.99y}{50}=5.93\\\\4.99x+5.99y=296.5](https://tex.z-dn.net/?f=%5Cdfrac%7B4.99x%2B5.99y%7D%7B50%7D%3D5.93%5C%5C%5C%5C4.99x%2B5.99y%3D296.5)
Solving the two equations by elimination method,
![4.99x+5.99y-4.99(x+y)=296.5-4.99(50)\\y=47\\x = 50-y=3](https://tex.z-dn.net/?f=4.99x%2B5.99y-4.99%28x%2By%29%3D296.5-4.99%2850%29%5C%5Cy%3D47%5C%5Cx%20%3D%2050-y%3D3)
Thus, the mixture contains 47 lb of Colombian Supreme and 3 lb of Mocha Java.