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Julli [10]
4 years ago
8

Evaluate x 3 for x = 2.

Mathematics
1 answer:
solong [7]4 years ago
6 0
If you mean 3x then that would be 6

hope this helps you
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Five Identical semicircles are arranged as shown.<br> Find the diameter of one circle
Arte-miy333 [17]

The diameter of one circle is 28 units

Find the diagram shown below:

Considering the semi-circle at the centre.

  • Let the unknown distance from the left be x:
  • Let the unknown distance from the right be y:

To get the value of "x"

x + 16  = 22

x = 22 - 16

x = 6

To get the value of "x"

16 +y  = 22

y = 22 - 16

y = 6

Diameter of one of the circle = x + 16 + y

Diameter of one of the circle = 6 + 16 + 6

Diameter of one of the circle = 28

Hence the diameter of one circle is 28 units

Learn more on diameter of circle: brainly.com/question/23220731

6 0
3 years ago
What is x-10=12 find x​
Luba_88 [7]

Answer:

X is 22

Step-by-step explanation:

7 0
3 years ago
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Which function has an inverse function?
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F(x)=x^5-3 is the answere
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Plz answer this ASAP! What is the x-coordinate of the solution for the system of equations? {y−x=910+2x=−2y Enter your answer in
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5 0
3 years ago
A simple random sample (SRS) of 150 is taken from a population with a 0.6 proportion of success. An independent SRS of 250 is ta
Virty [35]

Answer:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

Step-by-step explanation:

For this case we have the following data:

n_1 =150 represent the random sample 1 selected

\hat p_1 =0.6 represent the proportion of success for the sample 1 selected

n_2 =250 represent the random sample 2 selected

\hat p_2 =0.3 represent the proportion of success for the sample 2 selected

We know for this case that we can use the normal approximation since for both cases we have:

n_1 p_1  =90 \geq 10, n_1 (1-p_1)=60 \geq 10

n_2 p_2  =75 \geq 10, n_2 (1-p_2)=175 \geq 10

We have the randomization condition and we assume that the two samples are <10% of the entire population size.

So then we can use the following distribution for the proportions:

p \sim N( \hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

For this case we want to find the distribution for the difference of these two proportions and we have this:

p_1 -p_2 \sim N (\hat p_1 -\hat p_2 , \sqrt{\frac{\hat p_1 (1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}})

So then the dtandard deviation would be given by:

SE_{\hat p_1 -\hat p_2}= \sqrt{\frac{0.6(1-0.6)}{150}+\frac{0.3(1-0.3)}{250}}= 0.0494

4 0
4 years ago
Read 2 more answers
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