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lesantik [10]
4 years ago
10

The expression square root of 576/64 in simplest form is

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
5 0

Answer:

Just did it

The answer is 3

Step-by-step explanation:

forsale [732]4 years ago
4 0
The calculation is:   \sqrt{ \frac{576}{64} } = \sqrt{9} = 3

I see you have doubts, so I will explain each step.

Step 1: simpliy 576 / 64. In this case when you divide 576 by 64 you get 9 that is a whole number, so that is its simplest form.

Step 2: Calculate the square root of 9, which is 3.

If you use a simple calculator you will obtain that, but the square root of 9 is a calculation that you should know by  yourself.

Remember that the square root a number N is the number that multiplied by itself results in the number N. For example the squere root of 4 is 2, because 2 times 2 is 4. So, the square root of 9 is 3 because 3 times 3 is 9.

It will be very helpful for you to learn the 12 first squares because with that you will be able to tell the square roots of the most elemental numbers:

1^2 = 1 => √1 = 1

2^2 = 4 => √4 = 2

3^2 = 9 => √9 = 3

4^2 = 16 => √16 = 4

5^2 = 25 => 25 = 5

6^2 = 36 => √36 = 6

7^2 = 49 => √49 = 7

8^2 = 64 => √64 = 8

9^2 = 81 => √81 = 9

10^2 = 100 => √100 = 10

11^2 = 121 => √121 = 11

12^2 = 144 => √144 = 12
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3 years ago
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
Work out, giving your answer in its simplest form:<br>5/<br>14<br>x<br>7/<br>30​
Elena L [17]
X in (-oo:+oo)

((5/14)*x^7)/30 = 0

1/84*x^7 = 0 // : 1/84

x^7 = 0

x = 0

x = 0
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Answer:

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Step-by-step explanation:

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