The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
15x<130+20, 15x<150 divided both sides by 15 ,the answer is 10
14+5x=3(-x+3)-11
14+5x=-3x+9-11
14+5x=-3x-2
add 2 to both sides
16+5x=-3x
subtract 5x from both sides
16=-8x
divide both sides by -8
-2=x
Hope this helps! :)
First is 7 second is 8 third is 3