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telo118 [61]
4 years ago
8

Will someone please help me quickly here

Mathematics
1 answer:
babunello [35]4 years ago
6 0

To find out total costs after tax simply set up a proportion. Here is my work:

1. 6.25/100 = 707.98/x (part/whole = is/of)

2. Cross multiply to get 707.98(100) = 6.25(x)

3. Solve 70798 = 6.25x by dividing to get x = 11327.68.

After the sales tax, your total is $11327.68. Hope this helped :))

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The designers of drink cartons must consider the length of the straw required so that it will reach the bottom
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Answer:

<em>The length of the straw is 13.53 cm</em>

Step-by-step explanation:

<u>Rectangular Prism</u>

A rectangular prism or cuboid is a box-shaped object. It has six flat faces and all angles are right angles. And all of its faces are rectangles.

If the straw must reach into the diagonally opposite corners of the base of the carton, then its minimum length is calculated by:

d^2= a^2+b^2+c^2

Where a,b, and c are the dimensions of the cuboid. The image shows the dimensions of the drink carton: a=6 cm, b=10 cm, c=4 cm (order is not important), thus:

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d=\sqrt{152}

d= 12.33 cm

The straw must stick out of the carton by an additional 1.5 cm, thus the total length of the straw is: 12.33 + 1.5 = 13.53 cm

4 0
3 years ago
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Ruiz needs to buy a countertop for a kitchen. He calculated the area to be 16 square feet. The actual area is 15.4 square feet.
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Answer: 3.9%

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First, subtract the two values:

16 - 15.4 = 0.6

Now divide this to the actual area:

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Multiply by 100:

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Answer:

every group of her community

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To get an appropriate sample for her survey, she needs to survey people from various groups of the community.

If she surveys only dog owners, even only pet owners, chances are most people in that group would be in favor of the park, biased sample.

If she surveys only non-pet owners, the results will most likely show a minority of support.

The pet owners (or just dog owners) should be surveyed in a relative proportion of the general population of the community, so their opinion is neither over-weighted nor under-weighted in the results.

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