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3 years ago

. Write an equation of the line that passes through (2, -1) and is parallel to the graph of y = 5x – 2.

Mathematics

1 answer:

REY [17]3 years ago

5 0

PARALLEL slopes always have the same slope no matter what because they are parallel

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A. The slope of the line will change from positive to negative

Novay_Z [31]

Answer:

The slope of the line will change from negative to positive

Step-by-step explanation:

the equation is in the form of y=mx+c and m is negative. By multiplying m with another negative number it turns positive, thus slope changes from negative to positive

3 0

3 years ago

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2.57 as a improper fraction

USPshnik [31]

Answer: 2 57/100 hope that helps

6 0

3 years ago

What is the sum of 1.57 and 6.88?

CaHeK987 [17]

Answer:

The answer would be B: 8 ones, 4 tenths, and 5 hundredths.

Explanation:

First, you would have to use the equation: 1.57 + 6.88 = ?

Do the math, and 1.57 + 6.88 = 8.45

Now look at the answer choices. You can automatically get rid of every answer choice but B because none of them have an 8 in the ones place.

5 0

3 years ago

Read 2 more answers

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

What is the explicit formula for the sequence?

Aleksandr [31]

Answer:

$a_{n}$ = n - 2

Step-by-step explanation:

Note the difference between consecutive terms is constant, that is

0 - (- 1) = 0 + 1 = 1

1 - 0 = 1

2 - 1 = 1

3 - 2 = 1

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 1 and d = 1, thus

$a_{n}$ = - 1 + n - 1 = n - 2

7 0

3 years ago