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attashe74 [19]
3 years ago
11

A penny and a nickel are tossed. Describe the sample space of the experiment.

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Sample space would be:

(H,H), (H,T), (T,T), (T,H)

Here I have used H for heads and T for Tails... first coin for penny second for nickel...ok

Did you understand???

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I need help with both pictures plz
jeyben [28]

Answer:

-25+12 is less

Step-by-step explanation

1st picture

-25+12=-13

40+-63=-23

2nd picture

Negative

Positive

Negative Negative

To find the answers just simply do the number in a calculator for example -6+64 put that in a calculator and it will help you. figure our number 5

5 0
2 years ago
9Find -18 + (-67). Show your work.
polet [3.4K]

Answer:

-85

Explanation:

Given the mathematical expression:

-18+(-67)

First, we recall the product of signs.

+\times-=-

So, first, we open the bracket:

-18+(-67)=-18-67

We then simplify:

=-85

The result is -85.

3 0
1 year ago
It was a busy evening at the restaurant. Ron waited on 48 tables for 3 hours. Joe served 45 customers in 5 hours. Sue waited on
Alex Ar [27]

Answer:

Sue

Step-by-step explanation:

34/2= 17 which is the highest out of them all.

7 0
2 years ago
Andrew is showing his work in simplifying -4.5 + 4.2 + 5.6 - 7.3. Identify
Hitman42 [59]

Answer:

hence the answer for given problem is -2, but andrew get -21.6 which is wrong

Step-by-step explanation:

8 0
1 year ago
Determine whether the following are subspaces of R2×2 : (a) Thesetofall2×2diagonalmatrices (b) The set of all 2 × 2 triangular m
Mrrafil [7]

A vector space V is a subspace of a vector space W if

  • V is non-empty,
  • for any two vectors v_1,v_2\inV we have v_1+v_2\in V, and
  • for any scalar k and v\in V we have kv\in V.

It's easy to show the first condition is met by all the sets in parts (a-g).

(a) is a subspace of \Bbb R^{2\times2} because adding any 2x2 diagonal matrices together, or multiplying one by some scalar, gives another diagonal matrix.

(b) and (c) are also subspaces for the same reasons.

(d) is not a subspace because \Bbb R^{2\times2} because this set of matrices does not contain the zero matrix.

(e), however, is a subspace. Any linear combination of matrices in this set always yields a matrix with 0 in row 1, column 1 entry.

(f) is a subspace. A symmetric matrix is one of the form

\begin{bmatrix}a&b\\b&c\end{bmatrix}

Adding two symmetric matrices gives another symmetric matrix:

\begin{bmatrix}a_1&b_1\\b_1&c_1\end{bmatrix}+\begin{bmatrix}a_2&b_2\\b_2&c_2\end{bmatrix}=\begin{bmatrix}a_1+a_2&b_1+b_2\\b_1+b_2&c_1+c_2\end{bmatrix}

(g) is not a subspace. Consider the matrices

\begin{bmatrix}1&0\\0&0\end{bmatrix},\begin{bmatrix}0&0\\0&1\end{bmatrix}

Both matrices have determinant 0, but their sum is the identity matrix with determinant 1.

4 0
3 years ago
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