Answer:
310,000
Step-by-step explanation:
Answer:
p(t) = 0.19e0.10t
=>p'(t) = 0.19e0.10t (0.10*1)
=>p'(t) = 0.019e0.10t
t = 0 represents 1994
for 2002, t=2002-1994 =8
in 2002
average price =p(8)
=>average price = 0.19e0.10*8
=>average price =0.422853... million
rate of increase =p'(8)
=>rate of increase = 0.019e0.10*8
=>rate of increase =0.0422853... million per year
p(8)=$ 0.42 million
p'(8)=$ 0.042 million per year
You have to slove the math problema
Answer:
c = 150 + 20b
Step-by-step explanation:
Given:
Ticket charges = $150
Each bag carry cost = $20
Find:
Relationship between bag(b) and cost(c)
Computation:
⇒ Total cost = Ticket charges + $20(number of bags)
⇒ c = 150 + 20(b)
⇒ c = 150 + 20b
Answer:
26
Step-by-step explanation:
2(9)-(-3)+5
2(9)+3+5
18+8
26
