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kirill [66]
3 years ago
10

Need help plzz help asap plzzzz plzz help 10 pionts

Mathematics
1 answer:
igomit [66]3 years ago
6 0
Ok this is kinda difficult so if i confuse you im so sorry.
x/5=10
to get rid of the 5 you have to multiply the 5 by itself and the 10 by 5. that looks like this=> x/5(5)=10(5)
then you end up with x=50 because you got rid of the 5 by multiplying it with the ten. Anyways to sum it up x=10
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What is the value of -4x + 12 if x = -4
Nezavi [6.7K]

Answer:

28

Step-by-step explanation:

substitute x for negative four -4(-4)+12=

solve -4 * -4= 16

add 16 and 12 equals 28

5 0
3 years ago
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Jen has 2 meters of taffy. She wants to give each of her 3 best friends an equal amount of taffy. How many centimeters of taffy
sammy [17]
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3 years ago
Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

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(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
Which point is not on the graph represented by y=x^2+2x-4
Illusion [34]
(-6,20) \\
x=-6 \\ y=20 \\ \Downarrow \\
20 \stackrel{?}{=} (-6)^2+2 \times (-6)-4 \\
20 \stackrel{?}{=} 36-12-4 \\
20 \stackrel{?}{=} 20 \\
20 = 20 \\
\hbox{the point is on the graph}

(-4,4) \\
x=-4 \\ y=4 \\ \Downarrow \\
4 \stackrel{?}{=} (-4)^2+2 \times (-4)-4 \\
4 \stackrel{?}{=} 16-8-4 \\
4 \stackrel{?}{=} 4 \\
4 = 4 \\
\hbox{the point is on the graph}

Both points are on the graph.
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