Parallel lines have the same slope, so the new line will have the same slope as does the given line (which you have not yet given us!). If the given line has slope m = 5, then
y-2 = 5(x-[-8]), or y-2 = 5(x+8).
alternatively, y = 2 + 5x + 40, or y = 5x + 42
Please go back, find the slope of the given line, and re-do this problem, reflecting the value of the given slope.
To answer this item, we combine all terms involving the variable z to only one side of the equation. All else will be placed on the other side of the equation. This is as follows,
-cz + 6z = tz + 83
Transposing,
-cz - tz + 6z = 83
Factoring z out,
z(-c - t + 6) = 83
Dividing the equation such that z will be left on one side of the equation,
<em> z = 83 / (-c - t + 6)</em>
Answer:
Yes.
2 feet
Step-by-step explanation:
Pieces of copper that Arsenio needs in total = 27 pieces
Length of each piece of copper tubing that he needs = 2/9 foot
Length of available tubing = 8 foot
Since, the length of each piece is 2/9 foot, the length of 27 pieces would be:

This means, Arsenio needs 6 feet in total for the copper tubing. Since he got 8 feet in total, he has sufficient amount of tubing available.
After making the 27 pieces, he will be left with 8 - 6 = 2 feet of tubing.
The answer is C. Using ASA postulate, prove that triangles PQS and PRS are similar triangles

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

AREA COVERED BY THE ANGLE IN A SEMI SPHERE


Total Area Of The Semi Sphere:-

Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-


Total Area - Area Under Unshaded Part

