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levacccp [35]
3 years ago
5

In Python,The sum of the elements in a tuple can be recusively calculated as follows:The sum of the elements in a tuple of size

0 is 0Otherwise, the sum is the value of the first element added to the sum of the rest of the elementsWrite a function named sum that accepts a tuple as an argument and returns the sum of the elements in the tuple.
Computers and Technology
1 answer:
andrezito [222]3 years ago
3 0

Answer:

Following are the program in the Python Programming Language.

# Define the function

def Sum(tu):

# Check if the tuple contain 0

 if len(tu)==0:

#Then, Return 0

   return 0

#Otherwise

 else:

#call the recursive function

   return tu[0]+Sum(tu[1:])

#Set tuple type variable

tu=(2,5,1,8,10)

#print and call the function

print("The sum of tuple is:",Sum(tu))

<u>Output:</u>

The sum of tuple is: 26

Explanation:

Here, we define a function "sum()" and pass an argument "tu" which stores the tuple type value, inside the function.

  • Set the if conditional statement to check condition is the length of the tuple is 0 then, return 0.
  • Otherwise, call and return the sum of the tuple which is recursively calculated and close the function.

Finally, set the tuple type variable "tu" and initialize the value in it then, print and call the function sum.

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Answer: False

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Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binar
Mashcka [7]

Answer:

Following are the code to this question:

def binarynumber(num):#defining a method binarynumber that accepts a parameter num

   x=""#defining a string variable x

   if (num!=0):#defining if condition to check number not equal to 0

       while (num>=1):#defining a loop that check value is grater then equal to one

           if (num %2==0):#defining if condition to check num is even

               x=x+"0" #add string value 0 in num variable

               num=num/2 #divide the value by 2

           else:#defining else block

               x=x+"1"#add string value 1 in num variable

               num=(num-1)/2#first subtract 1 into num variable then divide the value by 2

   else:

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   return "".join(reversed(x))#return value

num = int (input ("Enter any number: "))#defining num variable that input the integer value

print (binarynumber(num))#using print method to call method binarynumber with passing num parameter

Output:

Enter any number: 12

1100

Explanation:

  • In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
  • Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
  • Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
  • At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.    
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Answer:

Explanation:

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}

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