All categories

3 years ago

How to divide 48 by 5/8

1 answer:

4 0

Use the KCF method, or keep, change, flip.

1 ) Set up your expression: 48 / 5/8
2 ) Change the division symbol into multiplication : 48 x 5/8
3 ) Flip 5/8 : 48 x 8/5
4 ) Solve! If it helps,write 48 as 48/1. Just multiply as you would.

Answer: 384/5, or 76 4/5

You might be interested in

Evaluate the function for an input value of 3. f(x)= −4x 2 −3x−5

Serhud [2]

Answer:

- 50

Step-by-step explanation:

x = 3

f ( x ) = - 4x^2 - 3x - 5

f ( 3 )

= - 4 ( 3 )^2 - 3 ( 3 ) - 5

= - 4 ( 9 ) - 3 ( 3 ) - 5

= - 36 - 9 - 5

= - 50

5 0

3 years ago

The side length of a cube is (x^2-1/2). Determine the volume of the cube.

stellarik [79]

Answer:

Step-by-step explanation:

x^6 − (3x^4)/2 + (3x^2)/4 − 1/8

The volume of a cube is Length^3.

If a length is (x^2-1/2, then cube root it

It will then be (x^2-1/2) x (x^2-1/2) x (x^2-1/2).

FOIL each term and evaluvate

3 0

3 years ago

Read 2 more answers

Plzzz help if your smart

tiny-mole [99]

Answer:

3/4

Step-by-step explanation:

8 0

3 years ago

A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in

777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

Verify each statement

A) Each pack of folders has a volume of 60 cubic inches.

The statement is True

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

B) The box has a volume of about 720 cubic inches

The statement is True

Because

The volume of the box is equal to the volume of one pack of folders multiplied by 12

$V=(12)60=720\ in^{3}$

C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches

The statement is False

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}$

$900\ in^{3}\neq 1,200\ in^{3}$

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

The statement is True

Because

Applying proportion

$\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}$

$1,200\ in^{3}= 1,200\ in^{3}$

E) Each pack of folders has a volume of 24 cubic inches.

The statement is False

Because

The volume of each pack of folders is equal to

$V=(5)(12)(1)=60\ in^{3}$

7 0

4 years ago

A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A player applies a horizonta

stepladder [879]

Answer:

1) The speed after 5 seconds is 13. $\bar 8$ m/s

2) The distance traveled after 5 seconds is 34.7 $\bar 2$ meters

Step-by-step explanation:

1) The given parameters are;

The mass of the hockey puck, m = 0.18 kg

The horizontal force applied by the player, m = 0.5 N

The time at which the speed is calculated, t = 5 seconds after the force is applied

Therefore;

From the equation for the applied force, F = m × a. where a represents the acceleration, by substituting the known values get;

0.5 = 0.18 × a

∴ a = 0.5/0.18 = 50/18 = 25/9 = 2. $\bar 7$

a = 2. $\bar 7$ m/s²

The speed after 5 seconds is given from the kinematic equation, v = u + a·t

Where;

v = The final velocity

u = The initial velocity = 0 m/s

t = The time = 5 seconds

By substitution of the known values, we get;

v = 0 + 2. $\bar 7$ × 5 = 13. $\bar 8$

The speed after 5 seconds = 13. $\bar 8$ m/s

2) The distance traveled, s, after 5 seconds is given by the equation, s = u·t + 1/2·a·t²

From which we have;

s = 0 × 5 + 1/2 × 2. $\bar 7$ × 5² = 34.7 $\bar 2$

The distance traveled after 5 seconds = 34.7 $\bar 2$ meters

7 0

3 years ago