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3 years ago

7x to the power of 2 is a what is ita) monomialb) binomialc) Trinomial

1 answer:

4 0

You can use the prefixes to figure this out:
Mono: one
Bi: two
Tri: three

So, because there is only one term, it is a monomial.

You might be interested in

2(x + 4)2 = 20 solve by square roots

DanielleElmas [232]

Answer:

x = − 4 ± √ 10,

Step-by-step explanation:

2(x + 4)² = 20

=> 2(x + 4) (x + 4) = 20

=> 2x + 8 (x + 4) = 20

=> 2x² + 8x + 8x + 32 = 20

=> 2x² + 16x + 32 = 20

=> 2x² + 16x + 12 = 0

=> Now solve using the quadratic formula:

x = − 4 ± √ 10,

Radical form: − 4 ± √ 10,

Decimal form: -0.84, -7.16

Hope this helps!

5 0

3 years ago

Is the answer 2 to this question?

iragen [17]

Answer:

its 8

Step-by-step explanation:

use ratio solution ..

2 shampoo : 9 water

8 shampoo : 36 water

9x4 = 36

same goes too shampoo.. it needs to be multiplied with 4 as to get 36 water u multiplied 9 with 4

6 0

3 years ago

Read 2 more answers

Which number is between 7.17 x 10^4 and 8.17 x 10^5

xxTIMURxx [149]

Answer:

71701,71702, 71703 etc

Step-by-step explanation:

Given :

$7.17$ × $10^{4}$ and 8.17× $10^{5}$

Now

$7.17$ × $10^{4}$ =71700 and

8.17× $10^{5}$ =817000

There are so many numbers between 71700 and 817000

Like: 71701,71702, 71703 etc

8 0

3 years ago

Please I need hep, get free brainly :D

padilas [110]

Step-by-step explanation:

Formula:

$\boxed{a = 3.14(r)^{2} }$

r represents the radius.

The radius is 1/2 of the diameter.

Since 1/2 of 16 is 8, 8 is our radius.

Substitute:

$a = 3.14(8)^{2}$

Solve:

$a = 3.14(64)$

$a = 200.96in^{2}$

6 0

2 years ago

Read 2 more answers

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

7x to the power of 2 is a what is ita) monomialb) binomialc) Trinomial​

7x to the power of 2 is a what is ita) monomialb) binomialc) Trinomial