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adelina 88 [10]
3 years ago
6

7x to the power of 2 is a what is ita) monomialb) binomialc) Trinomial​

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0
You can use the prefixes to figure this out:
Mono: one
Bi: two
Tri: three

So, because there is only one term, it is a monomial.
You might be interested in
2(x + 4)2 = 20 solve by square roots
DanielleElmas [232]

Answer:

x =  − 4  ±  √ 10,

Step-by-step explanation:

2(x + 4)² = 20

=> 2(x + 4)  (x + 4) = 20

=> 2x + 8 (x + 4) = 20

=> 2x² + 8x + 8x + 32 = 20

=> 2x² + 16x + 32 = 20

=> 2x² + 16x + 12 = 0

=> Now solve using the quadratic formula:

x =  − 4  ±  √ 10,

Radical form: − 4  ±  √ 10,

Decimal form: -0.84, -7.16

Hope this helps!

5 0
3 years ago
Is the answer 2 to this question?
iragen [17]

Answer:

its 8

Step-by-step explanation:

use ratio solution ..

2 shampoo : 9 water

8 shampoo : 36 water

9x4 = 36

same goes too shampoo.. it needs to be multiplied with 4 as to get 36 water u multiplied 9 with 4

6 0
3 years ago
Read 2 more answers
Which number is between 7.17 x 10^4 and 8.17 x 10^5
xxTIMURxx [149]

Answer:

71701,71702, 71703 etc

Step-by-step explanation:

Given :

7.17×10^{4} and 8.17×10^{5}

Now

7.17×10^{4}=71700 and

8.17×10^{5}=817000

There are so many numbers between 71700 and 817000

Like: 71701,71702, 71703 etc

8 0
3 years ago
Please I need hep, get free brainly :D
padilas [110]

Step-by-step explanation:

<u>Formula:</u>

\boxed{a = 3.14(r)^{2} }

r represents the radius.

The radius is 1/2 of the diameter.

Since 1/2 of 16 is 8, 8 is our radius.

<u>Substitute:</u>

a = 3.14(8)^{2}

<u>Solve:</u>

a = 3.14(64)

a = 200.96in^{2}

6 0
2 years ago
Read 2 more answers
The following integral requires a preliminary step such as long division or a change of variables before using the method of par
shtirl [24]

Division yields

\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}

\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a

which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}

Now, in the integral we get

\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get

\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}

7 0
2 years ago
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