Answer:

Step-by-step explanation:
The <em>Richter scale</em>, the standard measure of earthquake intensity, is a <em>logarithmic scale</em>, specifically logarithmic <em>base 10</em>. This means that every time you go up 1 on the Richter scale, you get an earthquake that's 10 times as powerful (a 2.0 is 10x stronger than a 1.0, a 3.0 is 10x stronger than a 2.0, etc.).
How do we compare two earthquake's intensities then? As a measure of raw intensity, let's call a "standard earthquake" S. What's the magnitude of this earthquake? The magnitude is whatever <em>power of 10</em> S corresponds to; to write this relationship as an equation, we can say
, which we can rewrite in logarithmic form as
.
We're looking for the magnitude M of an earthquake 100 times larger than S, so reflect this, we can simply replace S with 100S, giving us the equation
.
To check to see if this equation is right, let's say we have an earthquake measuring a 3.0 on the Richter scale, so
. Since taking 100 times some intensity is the same as taking 10 times that intensity twice, we'd expect that more intense earthquake to be a 5.0. We can expand the equation
using the product rule for logarithms to get the equation

And using the fact that
and our assumption that
, we see that
as we wanted.
Slope of required equation = slope of given line = -3( since both lines are parallel). By slope point form, y - y1 = m( x - x1). y-2 = -3(x-(-3)). y-2 = -3x - 9. y = -3x - 7. Required equation is y= -3x - 7.
Answer:
45
Step-by-step explanation:
Since the values are relatively small substitute i = 1 to 5 into 3i and sum
(3 × 1) + (3 × 2) + (3 × 3) + (3 × 4) + (3 × 5)
= 3 + 6 + 9 + 12 + 15
= 45
8(8-6v)= using the distributive property
8*8 = 64
8*6v = 48v
8(8-6v) = 64-48v
214/1000 is this as a fraction