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Lelechka [254]
3 years ago
10

The sum of the roots of 8x² - 2x = 1 is: -1/4 1/4 -1/8

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0
8x^2 - 2x = 1
8x^2 - 2x - 1 = 0

(2 +/-√(-2)^2 - 4(8)(-1))/ 2(8)
(2 +/-√4 + 32) / 16
(2 +/-√36) / 16
(2 +/- 6) / 16

2+6/16
1/2

2-6/16
-1/4

now since they want the sum of the roots
1/2 - 1/4

sum = 1/4
madreJ [45]3 years ago
4 0
8x^2-2x-1=0

8x^2-4x+2x-1=0

4x(2x-1)+1(2x-1)=0

(4x+1)(2x-1)=0

x=1/2 and -1/4

So the sum is 1/2-1/4=1/4

1/4
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6-4x=6x-8x+8<br><br> find the value of x
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Answer:

x = -1

Step-by-step explanation:

6 − 4x = 6x − 8x + 8

Combine 6x and −8x to get −2x.

6 − 4x = −2x + 8

Add 2x to both sides.

6 − 4x + 2x = 8

Combine −4x and 2x to get −2x.

6 − 2x = 8

Subtract 6 from both sides.

−2x = 8 − 6

Subtract 6 from 8 to get 2.

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Divide both sides by −2.

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Divide 2 by −2 to get −1.

x = 1

Hope this helps and have a great day! =D

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Answer:

sin^2x+cos^2x=1 is used to prove the given equation.

Step-by-step explanation:

We have given an equation:

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And we have an identity:

sin^2x+cos^2x=1

\Rightarrow sin^2x=1-cos^2x

Hence, right hand side is equal to sin^2x.


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