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3 years ago

Help please how do I do this

Mathematics

2 answers:

erik [133]3 years ago

5 0

“Reflection” because it’s the same but reflected

salantis [7]3 years ago

4 0

The transaction that is being used is a reflection

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What function is a quadratic function

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100 points, will give brainliest!

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Hope you are doing well

Answer:

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3 years ago

If g(x) = 4x^2 - 16 were shifted 7 units to the right and 3 down, what would the

Kitty [74]

Answer:

The new equation is $h(x)=4(x-7)^2-19$

Step-by-step explanation:

Given : Function $g(x) = 4x^2 - 16$ were shifted 7 units to the right and 3 down.

To find : What would the new equation be?

Solution :

Shifting to the right with 'a' unit is

f(x)→f(x-a)

So, shifting g(x) 7 units to the right is

$h(x) = 4(x-7)^2-16$

Shifting to the down with 'b' unit is

f(x)→f(x)-b

So, shifting g(x) 3 units down is

$h(x)=(4(x-7)^2-16)-3$

$h(x)=4(x-7)^2-19$

The new equation is $h(x)=4(x-7)^2-19$

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3 years ago

What is the answer to 9x-7i>3(3x-7u)

Jlenok [28]

Answer:

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Step-by-step explanation:

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3 years ago

Find an equation of the tangent line to the hyperbola y = 3/x at the point (3, 1).

Vesna [10]

Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: $y'= \frac{x(0)-3(1)}{x^2}$ so $y'=- \frac{3}{x^2}$ . The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: $y'=- \frac{3}{3^2}=- \frac{3}{9}=- \frac{1}{3}$ . So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. $1=- \frac{1}{3}(3)+b$ so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is $y=- \frac{1}{3}x+2$

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3 years ago