Answer:
![0.8\ m](https://tex.z-dn.net/?f=0.8%5C%20m)
Step-by-step explanation:
In this problem we know that
The scale is equal to
![\frac{1}{250}\frac{m}{m}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B250%7D%5Cfrac%7Bm%7D%7Bm%7D)
so
by proportion
Find what will be the height of the scale model
![\frac{1}{250}\frac{m}{m}=\frac{x}{212}\frac{m}{m}\\ \\x=212/250\\ \\x= 0.848\ m](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B250%7D%5Cfrac%7Bm%7D%7Bm%7D%3D%5Cfrac%7Bx%7D%7B212%7D%5Cfrac%7Bm%7D%7Bm%7D%5C%5C%20%5C%5Cx%3D212%2F250%5C%5C%20%5C%5Cx%3D%200.848%5C%20m)
Round to the nearest tenth of a meter
![0.848\ m=0.8\ m](https://tex.z-dn.net/?f=0.848%5C%20m%3D0.8%5C%20m)
Answer:
∠MON = 57°
Step-by-step explanation:
∠LOM + ∠MON = ∠LON ← substitute values
3x + 20 + 2x + 33 = 113, that is
5x + 53 = 113 ( subtract 53 from both sides )
5x = 60 ( divide both sides by 5 )
x = 12
Hence
∠MON = 2x + 33 = (2 × 12) + 33 = 24 + 33 = 57°
I hope this helps. Sorry if this is wrong:( enjoy your day!!
Given:
m(ar LNM) = 280°
To find:
The value of y.
Solution:
Complete angle = 360°
m(ar LNM) + m(ar LM) = 360°
280° + m(ar LM) = 360°
Subtract 280° from both sides.
280° + m(ar LM) - 280° = 360° - 280°
m(ar LM) = 80°
Inscribed angle is equal to the half of the intercepted arc.
![$\Rightarrow \angle LNM = \frac{1}{2} m (ar\ LM )](https://tex.z-dn.net/?f=%24%5CRightarrow%20%5Cangle%20LNM%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20%28ar%5C%20%20LM%20%29)
![$\Rightarrow y= \frac{1}{2}(80^\circ )](https://tex.z-dn.net/?f=%24%5CRightarrow%20y%3D%20%5Cfrac%7B1%7D%7B2%7D%2880%5E%5Ccirc%20%29)
![$\Rightarrow y= 40^\circ](https://tex.z-dn.net/?f=%24%5CRightarrow%20y%3D%2040%5E%5Ccirc)
The value of y is 40 degrees.