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saw5 [17]
3 years ago
9

For the given function, find the vertical and horizontal asymptote(s) (if there are any).

Mathematics
1 answer:
Doss [256]3 years ago
8 0
There are three rules of finding the horizontal asymptote depending on the orders of the numerator and denominator. If the degrees are equal for the numerator and the denominator, then the horizontal asymptote is equal to y = the ratio of the coefficients of the highest order from the numerator and the denominator. If the degree in the numerator is less than the degree in the denominator, then there the x axis is the horizontal asymptote. If on the other hand, the order in the numerator is greater than that of the denominator, then there is no horizontal asymptote. 

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It’s #11 that I need help with
wel

#11

Perimeter:

P = 2(W + L)

P = 2(3.5 + 6.5)

P = 2(10)

P = 20 units


Area:

A = WL

A = 3.5 * 6.5

A = 22.75 square units


5 0
3 years ago
SONGS
adelina 88 [10]

Answer:

Step-by-step explanation:

why dont you like spinach?     it tastes bitter to me

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8 0
2 years ago
Find the greatest common factor of these three expressions.<br> 18u^3 , 45u^2 , and 27u
stiv31 [10]

Answer:

9u

Step-by-step explanation:

18u³ / 9u = 2u²

45u²/9u = 5u

27u / 9u = 3

4 0
3 years ago
Find for x<br><br> 1/5x + 1/3= 3(2/3x -2)
topjm [15]

Answer:

The value of x  for the given expression is  (95/27)

Step-by-step explanation:

Here, the given expression is:

\frac{1}{5} x + \frac{1}{3}   = 3(\frac{2}{3}x -2)

Now here  solving for the value of x , we get

\frac{1}{5} x + \frac{1}{3}   = 3(\frac{2}{3}x) -6\\\implies\frac{1}{5} x + \frac{1}{3}   = 2x -6

Now, taking the variable terms on 1 side, we get

\frac{1}{5} x   - 2x   = -6 -  \frac{1}{3} \\\implies\frac{x  - 10x}{5}   = -(\frac{6(3)  +1}{3} )

or, \frac{-9x}{5}   = -\frac{19}{3}   \implies x  = \frac{19}{3}  \times\frac{5}{9}   = \frac{95}{27}

Hence,  the value of x = (95/27)

6 0
3 years ago
Hello I’m trying to solve this problem I just don’t know how to do it.
Katyanochek1 [597]

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

3 0
3 years ago
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