Answer:
2
Step-by-step explanation:
just add them common sense just saying!!
• Expand (2a + b)²:
(2a + b)²
= (2a + b) · (2a + b)
Multiply out the brackets by applying the distributive property of multiplication:
= (2a + b) · 2a + (2a + b) · b
= 2a · 2a + b · 2a + 2a · b + b · b
= 2²a² + 2ab + 2ab + b²
Now, group like terms together, and you get
= 2²a² + 4ab + b²
= 4a² + 4ab + b² <——— expanded form (this is the answer).
I hope this helps. =)
Tags: <em>special product square of a sum algebra</em>
Cos Ф - cos Ф.sin² Ф
sin² Ф = 1 - cos² Ф
cos Ф - cos Ф( 1-cos² Ф) = cos Ф - cos Ф - cos³ Ф = cos³ Ф
cos Ф - cos Ф.sin² Ф = cos³ Ф
the sum of 1+3+5+7+1209 is.....1225
Answer:
x = 2, and 6
x = 2 , 6
Step-by-step explanation:
The quadratic function to analyze is: 
In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".
The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).
So, there are two x-intercepts: x= 2, and 6