Are you sure you wrote it right because it should be -42.99
Show me a picture of the equation
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
1 Simplify \frac{4}{15}x
15
4
x to \frac{4x}{15}
15
4x \frac{4x}{15}=1.44
4x =1.44
2 Multiply both sides by 1515.
4x=1.44\times 15
4x=1.44×15
3 Simplify 1.44\times 151.44×15 to 21.621.6.
4x=21.6
4x=21.6
4 Divide both sides by 44.
x=\frac{21.6}{4}
x= 4
21.65 Simplify \frac{21.6}{4} 421.6 to 5.45.4.
x=5.4
x=5.4
Answer:
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Answer:
d–intercept is simply the value of t when d equals zero. Which this case is when he reaches it his destination.
