Answer:
Step-by-step explanation:
step 1
Find the slope of the given line
we have
(-3,2) and (0,1)
The slope m is
step 2
Find the slope of the line perpendicular to the given line
Remember that
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of its slopes is -1)
so
The slope is
step 3
Find the equation of the line in point slope form
we have
----> equation in point slope form
Convert to slope intercept form
2.8M/(365x24x60)=wonder why you need this
Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
5(3 +x) – 2 = (5+3)*(5+x)
(8-2)*(5x-2)
6*5x-2
this Is what I came up with.
Answer: The correct option is
(E) 80,000.
Step-by-step explanation: Given that after adding 4,000 gallons of water to a large tank that was already filled to 
of its capacity, the tank was then at 
of its capacity.
We are to find the number of gallons of water that the tank hold when filled to capacity.
Let the tank can hold x gallons of water when filled to capacity.
Then, according to the given information, we have
Thus, the required capacity of the tank is 80,000 gallons of water.
Option (E) is CORRECT.
