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ddd [48]
3 years ago
10

If N = , r = , and n = , and assuming that X has a hypergeometric probability distribution, compute the following. Write your an

swers as fractions. (a) P(X = 2) =ans7 (b) P(X ≤ 1) =ans8 Click if you would like to Show Work for this question:
Mathematics
1 answer:
artcher [175]3 years ago
4 0

Answer:

(a) The value of P (X = 2) is 0.3571.

(b) The value of P (X ≤ 1) is 0.5952.

Step-by-step explanation:

A Hypergeometric distribution is used to describe the probability distribution of <em>x</em> successes in <em>n</em> random draws from a population of size <em>N </em>that contains exactly <em>r</em> items that are considered as success. In this distribution each draw results in either a success or a failure.

The probability mass function of Hypergeometric distribution is:

P(X=x)=\frac{{r\choose x}{N-r\choose n-x}}{{N\choose n}}

Given:

N = 9

r = 3

n = 4

(a)

Compute the value of P (X = 2) as follows:

P(X=2)=\frac{{3\choose 2}{9-3\choose 4-2}}{{9\choose 4}}=\frac{3\times 15}{126}=0.3571

Thus, the value of P (X = 2) is 0.3571.

(b)

Compute the value of P (X ≤ 1) as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             =\frac{{3\choose 0}{9-3\choose 4-0}}{{9\choose 4}}+\frac{{3\choose 1}{9-3\choose 4-1}}{{9\choose 4}}\\=0.1190+0.4762\\=0.5952

Thus, the value of P (X ≤ 1) is 0.5952.

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