Answer:
m2WXW-90 and YZ parallel to YZ
Step-by-step explanation:
Answer:
x=-3
Step-by-step explanation:
f(x)=-2(x+3)^2-5
The equation is in the form
f(x) = a(x-h)^2 -k
where (h,k) is the vertex
The h value is also the axis of symmetry
f(x)=-2(x--3)^2-5
The vertex is (-3,-5)
so the axis of symmetry is x=-3
(0,5.25)(10,13.75)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (13.75 - 5.25) / (10 - 0) = 8.5/10 = 0.85
y = mx + b
(0,5.25)...x = 0 and y = 5.25
slope(m) = 0.85
now we sub, we r looking for b, the y int
5.25 = 0.85(0) + b
5.25 = b
so ur equation is : y = 0.85x + 5.25 or C(t) = 0.85t + 5.25 <==
cost of a 12 min taxi ride.....sub in 12 for t
C(t) = 0.85t + 5.25
C(12) = 0.85(12) +5.25
C(12) = 10.20 + 5.25 = 15.45
so a 12 min ride would cost u : $ 15.45 <==
2 lines are skew if they are neither parallel, nor intersecting.
If 2 lines are parallel or intersecting, they form a plane, so they are coplanar. So "skew" is the opposite or complement of "coplanar".
i) a and b: are both on M so coplanar, not skew
ii) b is in M, c is in N and they have no common point, so skew. (if they had a common point that would be a point in the line d of intersections of planes M and N, but they dont meet at such a point)
iii) b and e: are both on M so coplanar, not skew
iv) e and c : skew, same argument as ii.
v) a and e : are both on M so coplanar, not skew
vi) a and c: a is in M, c is in N. If they met, they would met at a point on line d, the only set of points common to planes M and N, but they dont. so skew