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3 years ago

×+28=53 what is the value of ×

Mathematics

1 answer:

Lena [83]3 years ago

6 0

X=25

because you subtract 28 away from 53

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What are the names of the three eras identified on the x-axis in model 1 answers?

Svetllana [295]

<span>The names of the three eras identified on the x-axis in model 1 answers are Paleozoic, Mesozoic and Cenozoic. It can be seen from the graph that a mass extinction happened 444 million years ago in Paleozoic era, another happened 254 million years ago at end of Paleozoic era and marked the beginning of Mesozoic era. The final mass extinction happened 65 million years ago at end of Mesozoic era in which dinosaurs went extinct.</span>

3 0

3 years ago

Look at the table to answer the question.

Alexus [3.1K]

Answer:

Your power function is y=-2 $x^{2}$

Step-by-step explanation:

The way I found it was.

0=0, so, the function multiply by zero, and have no other term to add

A number (one in a case) gives as a result: -2. So, one, elevated to ANY power results in one, every time. So, I have 1, as a factor and -2 as a result. One is as well a factor that delivers a result equal to the other factor. (3)(1)=3 , (8987)(1)=8987. So, the other factor must be -2

Then I checked all the table, and the results were consistent.

5 0

2 years ago

Write as a single power of 6<br> (6^5)^4

babunello [35]

Answer:

6^20

Step-by-step explanation:

When two indices are in brackets, you just have to multiply them.

3 0

3 years ago

A culture started with 3000 bacteria. After 4 hours, it grew to 3,600 bacteria. Predict how many bacteria will be present after

Vlad [161]

Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

$A = A_ob^t$
$3600 = 3000b^4$

Now we solve for b
$3600 = 3000b^4$
$\frac{3600}{3000} = \frac{3000b^{4}}{3000}$
$\frac{6}{5} = b^4$
$\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}$
$\sqrt[4]{\frac{6}{5}} = b$

Now that we have found b, we can use the equation $A = 3000b^t$ to predict how many bacteria will be present after 10 hours.
$b = \sqrt[4]{\frac{6}{5}}$
t = 10
$A = 3000b^t$
$A = 3000\sqrt[4]{\frac{6}{5}}^{10} = 4732.3228 = 4732$

Answer = 4732

4 0

3 years ago

Please help me solve this whole problem!

Dvinal [7]

I’m not good at math srry but hope someone answers the is for you

3 0

2 years ago

Read 2 more answers