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Vinil7 [7]
3 years ago
14

Pierce is making a rectangular frame for a photo collage that has a perimeter of 72.2 72.2 inches. The length of the frame is 20

.3 20.3 inches. Write an equation to find the width of the frame, x
Mathematics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

Step-by-step explanation:

For this case we know that the photo is rectangular. Let's define:

x = the width,  y= the length

And we know that the perimeter is given by:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

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3y = x + 9
y = (x/3) + (9/3)
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7 0
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It snowed from 9:43 PM to 11:37 PM. How long was it snowing?
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4 0
2 years ago
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A rose garden in the city park is rectangular and is 9m wide. If the area of the rectangle is 144m, what is the length of the ga
Keith_Richards [23]

Answer:

So 144 divided by 9 equals 16 so the length is 16. Cause 16 x 9 = 144 Your Welcome !

Step-by-step explanation:

4 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Match the systems of equations with their solutions.
Oksanka [162]

Answer:

See explanation for matching pairs

Step-by-step explanation:

Equations

(1)

x - y = 25

2x + 3y = 180  

(2)

2x - 3y = -5

11x + y = 550  

(3)

x - y = 19

-12x + y = 168

Solutions

(-17,-36)

(47, 33)

(51, 26)

Required

Match equations with solutions

(1) x - y = 25 and 2x + 3y = 180

Make x the subject in: x - y = 25

x = 25 + y

Substitute x = 25 + y in 2x + 3y = 180

2(25 + y) + 3y = 180

50 + 2y + 3y = 180

50 + 5y = 180

Collect like terms

5y = 180-50

5y = 130

Solve for y

y =26

Recall that: x = 25 + y

x = 25 + 26

x = 51

So:

(x,y) = (51,26)

(2)  2x - 3y = -5 and 11x + y = 550

Make y the subject in 11x + y = 550

y = 550 - 11x

Substitute y = 550 - 11x in 2x - 3y = -5

2x - 3(550 - 11x) = -5

2x - 1650 + 33x = -5

Collect like terms

2x  + 33x = -5+1650

35x = 1645

Solve for x

x = 47

Solve for y in y = 550 - 11x

y = 550 - 11 * 47

y = 550 - 517

y = 33

So:

(x,y) = (47,33)

(3)

x - y = 19  and -12x + y = 168

Make y the subject in -12x + y = 168

y = 168 + 12x

Substitute y = 168 + 12x in x - y = 19

x - 168 - 12x = 19

Collect like terms

x -12x = 168 + 19

-11x = 187

Solve for x

x = -17

Solve for y in y = 168 + 12x

y =168-12 *17

y =-36

So:

(x,y) = (-17,-36)

4 0
2 years ago
Find b and s. At The present time Mrs. B's age is six years more than four times her sons age. Three years ago she was seven tim
padilas [110]

Answer:

Mrs. B's age = y = 38 years

her son's age = x = 8 years

Step-by-step explanation:

To Find:

Mrs. B's age = y =?

her son's age = x = ?

Solution:

Let Mrs. B's age  be 'y' years

and her son's age be 'x' years

Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)

According to the first given condition,

y = 6 + 4x ...............Equation ( 1 )

According to the second given condition,

(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )

equating equation 1 in equation 2 we get

6 + 4x -3 = 7x - 21

7x - 4x = 21 + 3

∴ 3x=24\\\therefore x =\frac{24}{3} \\\\\therefore x =8\ years

Now substitute x in equation 1 we get

y = 6 + 4×8

y = 6 + 32

∴ y = 38 years

Mrs. B's age = y = 38 years

her son's age = x = 8 years

6 0
2 years ago
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