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MAXImum [283]
3 years ago
9

Help me out, please.

Mathematics
1 answer:
Sergio039 [100]3 years ago
5 0
Question 2 the answer is 4
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Please Help!!
gladu [14]

Annual rate: 500*0.07 = 35
Year 1: 35
Year 2: 35
Year 3: 35
Year 4: 35
Year 5: 35+500=535
Total=675

Compounded annually
Year 1: 500*1.05=525
Year 2: 525*1.05=551.25
Year 3: 551.25*1.05=578.8125=578.81
Year 4: 578.8125*1.05=607.753125=607.75
Year 5: 607.753125*1.05=638.14
7 0
4 years ago
Ryan and Sarah collect baseball cards. Ryan has 150 baseball cards and collects 10 cards per week. Sarah has 233 baseball cards
ICE Princess25 [194]

Answer:

About 17 weeks

Step-by-step explanation:

Given

Ryan:

Initial = 150

<em />Additional = 10<em> (weekly)</em>

Sarah:

Initial = 233

Additional = 5 (weekly)

Required

Determine the number of weeks they have the same cards

Represent the number of weeks with w:

For Both individuals, number of card at any given week is:

Initial + Additional * w

So,

For Ryan, the expression is:

150 + 10 * w

150 + 10w

For Sarah, the expression is:

233 + 5 * w

233 + 5 w

To determine the number of weeks, we have to equate both equations:

150 + 10w= 233 + 5 w

Collect Like Terms

10w - 5w = 233 - 150

5w = 83

Solve for w

w = 83/5

w = 16.6

16.6 implies about 17 weeks, because 16.6 approximates to 17

<em>Conclusively, Ryan and Sarah will have the same number of balls in about 17 weeks</em>

5 0
3 years ago
Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets
EleoNora [17]

Complete Question

Grandpa and Grandma are treating their family to the movies. Matinee tickets cost $4 per child and $4 per adult. Evening tickets cost $6 per child and $8 per adult. They plan on spending no more than $80 on the matinee tickets and no more than $100 on the evening tickets. Could they take 9 children and 4 adults to both shows? Show your work. A yes or no answer is not sufficient for credit.

Answer:

Yes it is  possible to take the  9 children and 4 adults to both shows

Step-by-step explanation:

From the question we are told that

    The  cost of the Matinee tickets for a child is  z =  $4

    The  cost of the Matinee tickets for an adult is  a  = $ 4

     The cost of the Evening tickets for  a child is  k =  $6

      The cost of the Evening tickets for an adult is  b =  $8    

      The  maximum amount to be spent on Matinee tickets is  m = $80

       The maximum amount to be spent on Evening tickets is  e =  $100

       The  number of child to be taken to the movies is  n  = 9

        The number of adults to be taken to the movies is  j  =  4

Now the total amount of money that would be spent on Matinee tickets is  mathematically evaluated as      

           t = 4 n + 4 j

substituting values

           t = 4 *  9  + 4* 4

           t =  52

Now the total amount of money that would be spent on  Evening ticket is mathematically evaluated as      

      T =  6n + 8j

substituting values

     T =  6(9) + 8(4)

    T = 86

This implies that it is possible to take 9 children and 4 adults to both shows

given that

      t \le m

i.e  $56  \le$ 80

and  

      T \le e

i.e   $ 86 \le $ 100

4 0
3 years ago
The ratio of boys to girls in Ms. Cunningham’s class is 2 to 3. There are 18 girls in the class.
OlgaM077 [116]

Answer:

30 students

Step-by-step explanation:

18 divided by 3 is 6

6 x 2 = 12

12 + 18 = 30

4 0
3 years ago
A store pays $10 for a bracelet
Ratling [72]

Answer:

same

Step-by-step explanation:

4 0
3 years ago
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