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MArishka [77]
3 years ago
9

Complete the statement. Round to the nearest hundredth if necessary. 75.2 in. ≈≈ cm

Mathematics
1 answer:
Zina [86]3 years ago
3 0
75 I believe is the correct answer!
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Can someone please help me with this question? Thank you!
kvasek [131]

Answer:

The arcs are not congruent which makes the statement false.

Step-by-step explanation: Congruent means equal to my understanding.


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You buy a computer for $3,000. Its value depreciates by 8% every month. Write an equation to represent the situation. How much i
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y=3,000(0.92)^x

Step-by-step explanation:

your computer is worth $2, 336.04

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∠A and ​ ∠B ​ are vertical angles with m∠A=x and m∠B=4x−30 .<br><br> What is m∠A ?
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3 years ago
What's the product of (1/3x^2y)*(1/6xy^3)
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5 0
2 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

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⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
2 years ago
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