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valina [46]
3 years ago
6

A squirrel climbs 15 feet up a tree. He then runs 8.26 feet down the tree. How much further does the squirrel need to go before

reaching the ground?
Mathematics
2 answers:
SVEN [57.7K]3 years ago
8 0

Answer:

6.74 feet.

Step-by-step explanation:

We have been given that a squirrel climbs 15 feet up a tree. He then runs 8.26 feet down the tree.

To find the distance that squirrel need to go before reaching the ground, we will subtract distance traveled downwards from the distance traveled upwards by squirrel.

\text{Squirrel needs to cover distance}=\text{15 feet}-\text{8.26 feet}

\text{Squirrel needs to cover distance}=6.74\text{ feet}

Therefore, squirrel needs to go 6.74 feet before reaching the ground.

Lostsunrise [7]3 years ago
4 0
That would be 15 - 8.26 = 6.74 feet
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Answer:

a) S= {HH, HT, TH, TT}

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And we have the following table:

X     |     0   |     1   |      2

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Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

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The sampling space on this case is given by:

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The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

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And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

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