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aleksklad [387]
3 years ago
7

Consider the graph of the quadratic function y = –2(x + 2)2 – 1 with no real zeros. What number can be added to the right side o

f the equation to change it to a function with one real root?

Mathematics
2 answers:
guapka [62]3 years ago
6 0

Answer:

The number is +1

Step-by-step explanation:

we have

y=-2(x+2)^2-1

This is the equation of a vertical parabola with vertex at point (-2,-1)

The function has no real zeros

we know that

If the number +1 is added to the equation on the right side

then

y=-2(x+2)^2-1+1 -------> y=-2(x+2)^2

Is a translation one unit up

The vertex of the parabola will be the point (-2,0) and the function will have one real root

see the attached figure to better understand the problem

vlada-n [284]3 years ago
3 0

Answer:

The answer is 1 on Edgenuty

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pretty sure its 2 mugs

Step-by-step explanation: i might be wrong

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3 years ago
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Which point lies on the graph of the function shown below y=-x^2+5x-3
Andrei [34K]

Answer:

C: (2,3)

Step-by-step explanation:

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4 0
4 years ago
Hamburger Hut sells regular hamburgers as well as a larger burger. Either type can include cheese, relish, lettuce, tomato, must
Studentka2010 [4]

Answer:

a) 40 different hamburgers can be ordered with exactly three extras

b) 20 different regular hamburgers can be ordered with exactly three extras

c) 7 different regular hamburgers can be ordered with at least five extras

Step-by-step explanation:

The order in which the extras are ordered is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem:

2 options of hamburger(regular or larger)

6 options of extras(cheese, relish, lettuce, tomato, mustard, or catsup.).

(a) How many different hamburgers can be ordered with exactly three extras?

1 hamburger type, from a set of 2.

3 extras, from a set of 6. So

C_{2,1}*C_{6,3} = \frac{2!}{1!(2-1)!}*\frac{6!}{3!(6-3)!} = 2*20 = 40

40 different hamburgers can be ordered with exactly three extras

(b) How many different regular hamburgers can be ordered with exactly three extras?

3 extras, from a set of 6. So

C_{6,3} = \frac{6!}{3!(6-3)!} = 20

20 different regular hamburgers can be ordered with exactly three extras

(c) How many different regular hamburgers can be ordered with at least five extras?

Five extras:

5 extras, from a set of 6. So

C_{6,5} = \frac{6!}{5!(6-5)!} = 6

Six extras:

6 extras, from a set of 6. So

C_{6,6} = \frac{6!}{6!(6-6)!} = 1

6 + 1 = 7

7 different regular hamburgers can be ordered with at least five extras

8 0
3 years ago
Find a particular solution to y" - y' + 9y = 3 sin 3x
Dima020 [189]

Answer:

cos3x

Step-by-step explanation:

y" - y' + 9y = 3 sin 3x

D^{2}y-Dy+9y=3 sin3x

y=\frac{3 sin 3x}{(D^{2} -D+9}=3 sin 3x

here D^2 will be replaced by  \alpha^2 where \alpha is coefficient of x

y=\frac{3 sin 3x}{-3^{2} -D+9}

y=-3\frac{sin 3x}{D}

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6 0
4 years ago
If the diameter of an object is 6 ½ meters, find the radius.
KatRina [158]

Answer:

Step-by-step explanation:

Diameter = 13/2 m

Radius = 13/4m

5 0
3 years ago
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