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Sindrei [870]
3 years ago
14

SOLUTIONS FOR SYSTEMS OF EQUATIONS

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

The person below did great but,


1) the answer is actually Solving a 6 order system

Mrrafil [7]3 years ago
6 0

1. Solving an order system

 

2. Let us solve this one by combining the two equations:

2x – y = 7

2y = 4x – 14 --> y = 2x – 7

combine:

2x – (2x – 12) = 7

2x – 2x + 7 = 7

0 + 7 = 7

7 = 7

No variable at the end, therefore infinite solutions

 

3. From the given equations itself, we can see that this is impossible to have solutions, therefore:

{}

 

4. y – x = -1 --> y = x – 1

x + (x – 1) = -5

2x – 1 = -5

x = -2

 

y = x – 1 = -2 – 1 = -3

(-2, -3)

 

5. x = y

x + x = 4

2x = 4

x = 2 = y

(2, 2)

1 solution

 

6. x – y = 2 --> x = 2 + y

3 (2 + y) + 2y = 6

6 + 3y + 2y = 6

5y = 0

y = 0

 

x = 2 + y = 2

(0, 2)

1 solution

 

7. 4x + (x + 6) = 1

5x + 6 = 1

5x = -5

x = -1

 

y = x + 6 = -1 + 6 = 5

(-1, 5)

 

8. x – y = 5 --> x = 5 + y

2 (5 + y) + y = 1

10 + 2y + y = 1

3y = -9

y = -3

 

x = 5 + y = 5 – 3 = 2

(2, -3)

1 solution

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