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Ivanshal [37]
3 years ago
5

Simplify the expression: (-2-2i)(-4+6i)

Mathematics
2 answers:
Maurinko [17]3 years ago
5 0
(-2-2i)(-4+6i)
=8-12i+8i-12i^2
=8-4i-12i^2
=4(2-i-3i^2)
=4((i-1)(3i+2))
=4(i-1)(3i+2)
iren2701 [21]3 years ago
5 0

Answer: (-2-2i)(-4+6i) = 20 - 4i

Step-by-step explanation:

We have the expression:

(-2 - 2i)*(-4 + 6i)

the rule we need to know here is that i*i = -1

now, the first step is distribute the parentheses.

(-2 - 2i)*(-4 + 6i) = -2*-4 -2*6i - 2i*-4 - 2i*6i = 8 -12i + 8i -12*(i*i)

= 8 + (8 - 12)i +12 = 20 - 4i

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Jenna manipulated the equation 4x + 7=10 by adding -7 to both sides.Which of the follolwing properties justifies this manipulati
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3 years ago
Can someone help me out <br><br> What x value solves the equation?<br><br> 3x – 5 = 1<br><br> x =
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3 years ago
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\sum\limits_{k=1}^{\infty}12\left(0.7\right)^{k-1}

The infinite geometric series is converges if |r| < 1.

We have r = 0.7 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

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4 years ago
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