Answer:
solution given:
For triangle
side1=9ft
side2=10ft
base[b]=11ft
height[h]=7.7ft
and for rectangle
length [l]=3ft
wide [w]=9ft
Now
total surface area=lateral surface area +2curved surface area
=perimeter of triangle×length +2area of triangle
=(9+10+11)×3+2×1/2×2(½×b*h)
=90+11×7.7
=174.7
=175ft²is a required answer.
7/8 yrds of ribbon per bow
if you need 4 bows
7/8 x 4 = 28/8 = 3 1/2 yards of ribbon needed
So, each square on the grid is 10 inches in length and width
To find the dimension of the diagonal lengths, treat them like a hypotenuse so we can use the Pythagorean theorem.
a^2 + b^2 = c ^2
a and b are our length and width and c is the hypotenuse.
Make each diagonal length part of a triangle. There will then be 4 triangles to work with.
Triangle 1 (Top left)
Triangle 2 (Bottom left)
Triangle 3 (Top Right)
Triangle 4 (Bottom Right)
A right triangle made with the top left diagonal dimension will have a vertical dimension of 30 (10+10+10) and a horizontal dimension of 40 (10+10+10+10)
To find c or the hypotenuse, plug these into the Pythagorean theorem.
30^2 + 40^2 = c ^2
c^2 = 900 + 1600 = 2500
c = sqrt(2500) = 50
You will see that triangles 2, 3, and 4 have the same vertical and horizontal dimensions giving them the same value.
Now combine the dimensions
diagonal = 50+50+50+50 = 200
horizontal = 90+90 = 180
diagonal + horizontal = 380