If be=6y+2 and ce=4y+6, find y
1 answer:
The complete question is:
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
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Hey there! I'm happy to help!
Let's look at our diameters.
We want to see how many times greater the diameter of the IC 1101 is than the Milky Way. So, we will divide it's diameter by the diameter of the Milky Way.
We divide the numbers without exponents, giving us 5. Then, we divide the 10s with exponents. When dividing exponents, you subtract the numbers in the exponent to get your result. For example, x³÷x²=x
Therefore, your answer is 50.
Have a wonderful day! :D