If be=6y+2 and ce=4y+6, find y
1 answer:
The complete question is:
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
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Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the 2 other sides, that is
x² + 6² = 17²
x² + 36 = 289 ( subtract 36 from both sides )
x² = 253 ( take the square root of both sides )
x = → C
Check the picture below.
thus is at 0 = -16t² + 96t +640,
well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.
thus is at 0 = -16t² + 96t +640,
well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.
