If be=6y+2 and ce=4y+6, find y

Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

The complete question is:
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y

Answer:
y = 2

Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC

From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2

Hope this helps :)

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