If be=6y+2 and ce=4y+6, find y
1 answer:
The complete question is:
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
quadrilateral ABCD is a rectangle (see attached image)
If BE = 6y + 2 and CE = 4y + 6, find the value of y
Answer:
y = 2
Explanation:
We are given that the quadrilateral ABCD is a rectangle. This means that it has the following properties:
1- Its diagonals are equal. This means that: AC = BD
2- Diagonals bisect eqcah other. This means that: BE = ED and AE = EC
From the above, we can infer that:
BE = CE
This means that:
6y + 2 = 4y + 6
6y - 4y = 6 - 2
2y = 4
y = 4/2
y = 2
Hope this helps :)
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Answer:
A ≈ 40.3 cm²
Step-by-step explanation:
The area of right Δ ACD is calculated as
A = bh ( b is the base and h the perpendicular height )
Here A = 50.5, b = CD and h = AC , then
× 14 × AC = 50.5
7 AC = 50.5 ( divide both sides by 7 )
AC ≈ 7.214
The area of Δ ABC is calculated as
A = × BC × AC × sin36°
= 0.5 × 19 × 7.214 × sin36°
≈ 40.3 cm² ( to 3 sf )