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HACTEHA [7]
3 years ago
12

Hi! Okay I have a review from the 5th grade if someone can help me because I don't remember fractions it would be so helpful bec

ause I have 7 and a half minutes left on this!: What are the like units for 2/3 and 1/2?
Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0

Answer:

6

Step-by-step explanation:

deff fn [24]3 years ago
4 0

Answer:

Im sorry im not giving the answer but maybe this will help you remember:

Step-by-step explanation:

replacing given fractions with equivalent fractions in such a way as to produce an equivalent sum or difference of fractions with like denominators. For example, 2/3 + 5/4 = 8/12 + 15/12 = 23/12.

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A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at ​​ (−2,
Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}  

\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{64}=8

Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{25}=5

Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{64}=8

Now let us find distance between vertex D and vertex A.

\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}  

\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

\text{Total distance walked by Jared}=26  

Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

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3 years ago
Giant tortoises move very slowly. They can travel a distance of about 0.17 mile in 1hour. If it travels at the same speed, how f
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0.17 in 1 hour
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To the nearest whole number 16,671 is
Pepsi [2]

Answer:

Step-by-step explanation:

17

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