Complete question :
A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.
What are the measures of the angles in triangle ABC?
a) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°
b) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
d) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°
Answer:
c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
Step-by-step explanation:
Given:
Length AC = 7 inches
Length BC = 24 inches
Length AB = 25 inches
Since it is a right angle triangle,
m∠C = 90°
To find the measures of the angle in ∠A and ∠B, we have :
For ∠A:
∠A = 73.7°
For ∠B:

∠B = 16.26 ≈ 16.3°
Therefore,
m∠A = 73.7°
m∠B = 16.3°
m∠C = 90°
Answer:
4
Step-by-step explanation:
3+(-2) is the same as 3-2 which is 1. and since with multiple exponents you work from the top you have 4 to the power of 1^4. 1^4 is 1, so it's 4^1, which is 4.
Answer:
50%
Step-by-step explanation:
50 to 75 is a change of 50% (25 is the difference between the two numbers, and 25 is 50% of 50).
Answer:
divide both sides by 1m
u2-v2=T/1m
add -u2 both sides of the equation
-v2=T/1m -u2
divide both sides by -1
v2= u2 - T/1m
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