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Romashka [77]
3 years ago
9

Simplify the expression. (x^2 - 9)/(x^2 + 2x - 15)

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

We have

\frac{x^2-9}{x^2+2x-15}

\frac{\left(x+3\right)\left(x-3\right)}{x^2+2x-15}

\frac{\left(x+3\right)\left(x-3\right)}{\left(x-3\right)\left(x+5\right)}

\frac{x+3}{x+5}

∴The answer is D

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Elena-2011 [213]

Answer:x=2, y=1, z=-1

Step-by-step explanation:

Given

2x+y+z=4----1

x-y+3z=-2----2

-x+y+z=-2----3

Add 2 & 3 we get

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Put value of z in 1 & 2

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2x+y=5----3

x-y+3(-1)=-2

x-y=1------4

add 3 & 4 we get

x=2

Put x & z in 1

y=1

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no and yes

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What is the length of AC?<br><br> A. Square root of 2<br> B. Square root of 5<br> C. 3<br> D. 5
Aleksandr-060686 [28]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point A (-3, 2)

Point C (-1, 3)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute [DF]:                    d = \sqrt{(-1+3)^2+(3-2)^2}
  2. Add/Subtract:                       d = \sqrt{(2)^2+(1)^2}
  3. Exponents:                           d = \sqrt{4+1}
  4. Add:                                      d = \sqrt{5}
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