The value of x is x=1/10
This can also be written as:
X=0.1
X=10^-1
Yes 5,4 is y=x-1 actually anything can be those symbols as long as they add up to the Equation
<h2><u>Angles</u></h2>
<h3>If angle 1 is 140°, then find the measure of the other angles.</h3>
- ∠2 = <u>40°</u>
- ∠3 = <u>40°</u>
- ∠4 = <u>140°</u>
- ∠5 = <u>140°</u>
- ∠6 = <u>40°</u>
- ∠7 = <u>40°</u>
- ∠8 = <u>140°</u>
<u>Explanation:</u>
- The relationship between ∠1 and ∠2 are <u>supplementary angles</u>, so when you <u>add up their measurements, it will become 180°</u>. Simply subtract 180 and 140 to get the measure of ∠2. As well as ∠3, they're <u>linear pairs</u>. And they are also <u>supplementary</u>. To determine the measure of ∠6 and ∠7, notice the <u>relationship</u> between ∠2 and ∠6. As you noticed, it is <u>corresponding angles</u>. So they <u>have the same measurement</u>. If <u>∠2 = 40°</u>, then <u>∠6 = 40°</u>. As well as ∠7, because the relationship between ∠6 and ∠7 are <u>vertical pairs</u>. So the angle measurement of ∠7 is also <u>40°</u>.
- Meanwhile, the relationship between ∠1 and ∠4 are <u>vertical pairs</u>. It means they also <u>have the same measurement</u>. So ∠4 = <u>140°</u>. The relationship between ∠1 and ∠5 are <u>corresponding angles</u>, so they also <u>have the same measurement</u>. If <u>∠1 = 140°</u>, then <u>∠5 = 140°</u>. The relationship between ∠1 and ∠8 are <u>alternate exterior angles</u>, and they also <u>have the same measurement</u>. <u>If ∠1 = 140°</u>, then <u>∠8 = 140°</u>.
Wxndy~~
Answer:

Step-by-step explanation:
If t is the number of years, then 12t is the number of months interest is compounded. The interest rate (growth rate) used each month is 1/12 of the annual rate, so is
monthly growth rate = 2%/12 ≈ 0.167% = 0.00167
Then the monthly growth factor is ...
monthly growth factor = (1 + monthly growth rate) = 1.00167
The overall account value is the initial value multiplied by this growth factor a number of times equal to the number of months, 12t. Repeated multiplication is indicated by an exponent:
A = 1500(1.00167)^(12t) . . . . . . . matches the last choice
Answer:
when simplified and added this is what i got and when redone too over check i got it again hopefully this helps.