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Ivahew [28]
3 years ago
13

Analyze the scatterplot and determine the equation that

Mathematics
2 answers:
ozzi3 years ago
6 0

Answer:

Relationship is :linear

Rate of change : 3

Y-intercept : (0,1)

Equation that models the data : y=3x+1

Step-by-step explanation:

yarga [219]3 years ago
3 0

Answer:

Linear

3

(0,1)

y=3x+1

Step-by-step explanation:

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If you throw 3 dice, the probability of getting 3 sixes is 0.5%. The probability of getting no sixes is 57.9%. Find the probabil
PtichkaEL [24]

Answer:

A) 99.5%

B) 42.1%

Step-by-step explanation:

A) Since the probability of 3 sixes is 0.5%, the probability of less than 3 sixes (that is, zero, one, or two sixes) is 100% - 0.5%, or 99.5%

B ) Since the probability of no sixes is 57.9%, the probability of at least 1 six is 100% - 57.9%, or 42.1%

7 0
2 years ago
If x>2, then x^2-x-6/x^2-4
zysi [14]
X(exponent 2) - x - 6
-------------------------   =
x(exponent 2) -4 

(x-3)(x+2)
-------------   =
(x-2)(x+2)

Cancel out the x + 2 factors. 

x-3
----      <== ANSWER
x-2

Hope this helps! :)

3 0
3 years ago
PLEASE HURRY!! What is the location of point C?
ollegr [7]

Answer:

Step-by-step explanation:

-4,-5

4 0
3 years ago
Read 2 more answers
What is the answer to the equation X=3-(3x6)+2?
dolphi86 [110]
  x =  3 - (3×6) + 2.        We perform the operation in the bracket first.

  x =  3 - 18 + 2

  x =  -15 + 2 = 2 -15 = -13

 x  = -13
4 0
4 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
3 years ago
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