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kirill [66]
3 years ago
10

What set of numbers does 2.5 belong in?

Mathematics
1 answer:
Kruka [31]3 years ago
3 0
2.5 belongs woth numbers under 10 and decimals
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6 0
4 years ago
Which of the following describes bias that may arise from the results?
velikii [3]
Answer: I think A
Epian:
8 0
3 years ago
What is the inverse of the function f(x) = 2x – 10?
Lana71 [14]

Answer:

h(x)=\dfrac{x}{2}+5

Step-by-step explanation:

You are given the function f(x)=2x-10. To find the inverse function f^{-1}(x) do such steps:

1. Rewrite the function f(x) as

y=2x-10

2. Express x in terms of y:

y+10=2x\\ \\x=\dfrac{y}{2}+5

3. Change x into y and y into x:

y=\dfrac{x}{2}+5

Now, the inverse function is

f^{-1}(x)=\dfrac{x}{2}+5

7 0
4 years ago
Read 2 more answers
What are the related frequencies to the nearest hundredth of the columns of the two way table?
Eddi Din [679]

Answer: The relative frequency of column A in group 1=0.75

The relative frequency of column B in group 1=0.25

The relative frequency of column A in group 2=0.56

The relative frequency of column B in group 2=0.44

Step-by-step explanation:

The relative frequency is the ration of each frequency by the total value in particular group.

For group 1 : Total =102+34=136

The relative frequency of column A in group 1=\frac{102}{136}=0.75

The relative frequency of column B in group 1=\frac{34}{136}=0.25

For group 2 : Total =18+14=32

The relative frequency of column A in group 2=\frac{18}{32}=0.5625\approx0.56

The relative frequency of column B in group 2=\frac{18}{32}=0.4375\approx0.44

7 0
3 years ago
find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8
AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0
3 years ago
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