Answer:
Length of segment QV = 35 units
Step-by-step explanation:
As shown in the figure attached,
Diagonals of TQVS are perpendicular to each other. Therefore TQVS will be a kite. By the property of a kite,
"There are two pairs of the sides which are equal in measure."
Therefore, TS ≅ TQ and SV ≅QV
Since TS ≅ TQ,
3x + 2 = 29 [Given: TQ = 29 units]
3x = 29 - 2
3x = 27
x = 9
Another pair of the consecutive sides is,
SV ≅ QV ≅ (4x - 1)
By substituting the value of x,
QV = (4 × 9) - 1
= 36 - 1
= 35 units
Therefore, length of segment QV = 35 units
You could write a set of equations or use the interest formula, A(t)=P(1+r/n)^nt
where p equals the principal amount, r equals the rate/ percentage of interest, n equals the compounding periods and t equals time
Answer:
B
Step-by-step explanation:
Answer:
7 / 15
Step-by-step explanation:
Fraction before painting = 5/6
Fraction left after painting = 11/30
Fracrion used = difference of the fraction before painting and fraction left after painting
Fraction used = 5/6 - 11/30
Lowest common factor of 6 and 30 = 30
5/6 - 11/30 = (25 - 11) / 30 = 14/ 30
Fraction used = 14/30 = 7/15
The answer is going to be 8 and 80.
