Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
Answer:
828.7 hours.
Step-by-step explanation:
To answer a question in which the total time has to be calculated of all the activities, first of all, all the times have to be converted to a single form. There are two types: decimals and fractions. Convert the fractions into decimals.
Department A = 202.50 hours.
Department B = 212 3⁄4 hours = 212.75 hours.
Department C = 198.25 hours.
Department D = 215 1⁄5 hours = 215.20 hours.
Therefore, the total number of hours spent on this project by all four departments. is the sum of all the above numbers. 202.50 hours + 212.75 hours + 198.25 hours + 215.20 hours = 828.7 hours.
Therefore, the total time is 828.7 hours!!!
