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Nonamiya [84]
3 years ago
8

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

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Simplify 6x + 6 + 5x - 8. <br> 11x - 2 <br> 11x + 2<br> 9x
andriy [413]
11x-2; SInce you have to add 6x and 5x because they are 'like terms' meaning they share the same variable. You also add the 6 and the -8, which is basically doing 6-8, which equals -2. So, you put these two numbers together to get an expression of 11x-2.
3 0
3 years ago
Read 2 more answers
The base and height of the triangle to the right are multiplied by 4. Describe the change in the area.
Artemon [7]
Area would be 15 if base is 6m and height is 5m
So 6*4=24
5*4=20
Area would be 240 for the 2nd answer

240/15=16

The area is 16x bigger
5 0
3 years ago
A car increased price by 3/4. after the increase it was priced at £84 what was the original price???
olga55 [171]

Answer: I think this is how we do it but i am not sure the answer is 48

Step-by-step explanation:

if the price increase by 3/4 then that mean it total will be 7/4 as 4/4 is it original price add so 7/4=84/x 84x4 is 336 336 divide by 7 is 48 to check 48 x 7/4 or 48 x 3/4 and add 48 if u math is correct than u should get 84

6 0
3 years ago
a wheelchair ramp is 9 feet long and sits 2.5 ft high. how long will a similar ramp be if it sits 1.5 ft high from the ground
bixtya [17]
The second ramp should be 5.4 ft long

6 0
3 years ago
Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
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