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Aliun [14]
3 years ago
5

Please help Evaluate the expression. (7 – 4)[(5 +

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0
You have to subtract 4 from 7 and then add 5 and 3 then add 8 and 2 then multiply 10 with 3 to get 30. 
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A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is
Grace [21]

Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

x=300tan32=187.460805573

(length of building + flagpole)

find length of building

tan 30 = x/300

x=173.205080757

subtract

187.460805573-173.205080757=14.255724816

round, length of flagpole = 14 feet

7 0
3 years ago
Please show work if you do, ( and get it right) I will make you brainliest!!!
DerKrebs [107]

Answer:

The percentage increase in bird population in the second years is 4%  .

Step-by-step explanation:

Given as :

During two years, the population of birds of an island became 7 times more than before.

The the percentage increase in first year = = r_1 =40%

Let The percentage increase in second year =  r_2 = r%

So, According to question

The initial population of bird = x

The increase population of bird =7 times before = 7 x

Now,

The increase population of bird = initial population of bird × (1+ \dfrac{r_1}{100}) ×  (1+ \dfrac{r_2}{100})

Or, 7 x = x × (1+ \dfrac{40}{100}) ×  (1+ \dfrac{r}{100})

Or, \dfrac{7 x}{x} = 1.4 ×  (1+ \dfrac{r}{100})

Or, 7 = 1.4 ×  (1+ \dfrac{r}{100})

Or, \dfrac{7 }{1.4} = (1+ \dfrac{r}{100})

Or, 5 = (1+ \dfrac{r}{100})

Or, (1+ \dfrac{r}{100}) = 5

Or, \dfrac{r}{100} = 5 - 1

Or,  \dfrac{r}{100} = 4

∴ r = 4 × 100

I.e r = 400

so, The percentage increase = r% = 4

Hence The percentage increase in bird population in the second years is 4%  . Answer

3 0
3 years ago
What is (0.3)⋅(0.5)?
Harman [31]

Answer:

0.15

Step-by-step explanation:

6 0
2 years ago
I need help with this ASAP plzzzzz
miss Akunina [59]

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

5 0
3 years ago
The Walnut Cove Ruritan Club sells hot dogs and drinks from a concession stand at the annual July 4 parade. Carl bought 6 hot do
pickupchik [31]

Based on the two different purchases, you can write equations for the price of a hotdog (h) and that of a drink (d). These equations can be solved by your favorite method to find the individual prices.

... 6h +4d = 17.00 . . . . . . Carl's purchase

... 3h +4d = 12.50 . . . . . . Susan's purchase

We can see that the difference in purchase cost (of $4.50) is due entirely to the difference in the number of hotdogs (3). Thus, the price of a hotdog must be

... $4.50/3 = $1.50

The 4 drinks are then ($12.50 -4.50) = $8, so must be $2 each. You don't need to figure the cost of a drink to determine that the appropriate answer choice is ...

... D. $1.50 for a hot dog; $2.00 for a drink.

5 0
3 years ago
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