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3 years ago

Please help Evaluate the expression. (7 – 4)[(5 +

Mathematics

1 answer:

IgorLugansk [536]3 years ago

8 0

You have to subtract 4 from 7 and then add 5 and 3 then add 8 and 2 then multiply 10 with 3 to get 30.

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A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is

Grace [21]

Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

x=300tan32=187.460805573

(length of building + flagpole)

find length of building

tan 30 = x/300

x=173.205080757

subtract

187.460805573-173.205080757=14.255724816

round, length of flagpole = 14 feet

7 0

3 years ago

Please show work if you do, ( and get it right) I will make you brainliest!!!

DerKrebs [107]

Answer:

The percentage increase in bird population in the second years is 4% .

Step-by-step explanation:

Given as :

During two years, the population of birds of an island became 7 times more than before.

The the percentage increase in first year = = $r_1$ =40%

Let The percentage increase in second year = $r_2$ = r%

So, According to question

The initial population of bird = x

The increase population of bird =7 times before = 7 x

Now,

The increase population of bird = initial population of bird × (1+ $\dfrac{r_1}{100}$ ) × (1+ $\dfrac{r_2}{100}$ )

Or, 7 x = x × (1+ $\dfrac{40}{100}$ ) × (1+ $\dfrac{r}{100}$ )

Or, $\dfrac{7 x}{x}$ = 1.4 × (1+ $\dfrac{r}{100}$ )

Or, 7 = 1.4 × (1+ $\dfrac{r}{100}$ )

Or, $\dfrac{7 }{1.4}$ = (1+ $\dfrac{r}{100}$ )

Or, 5 = (1+ $\dfrac{r}{100}$ )

Or, (1+ $\dfrac{r}{100}$ ) = 5

Or, $\dfrac{r}{100}$ = 5 - 1

Or, $\dfrac{r}{100}$ = 4

∴ r = 4 × 100

I.e r = 400

so, The percentage increase = r% = 4

Hence The percentage increase in bird population in the second years is 4% . Answer

3 0

3 years ago

What is (0.3)⋅(0.5)?

Harman [31]

Answer:

0.15

Step-by-step explanation:

6 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago

The Walnut Cove Ruritan Club sells hot dogs and drinks from a concession stand at the annual July 4 parade. Carl bought 6 hot do

pickupchik [31]

Based on the two different purchases, you can write equations for the price of a hotdog (h) and that of a drink (d). These equations can be solved by your favorite method to find the individual prices.

... 6h +4d = 17.00 . . . . . . Carl's purchase

... 3h +4d = 12.50 . . . . . . Susan's purchase

We can see that the difference in purchase cost (of $4.50) is due entirely to the difference in the number of hotdogs (3). Thus, the price of a hotdog must be

... $4.50/3 = $1.50

The 4 drinks are then ($12.50 -4.50) = $8, so must be $2 each. You don't need to figure the cost of a drink to determine that the appropriate answer choice is ...

... D. $1.50 for a hot dog; $2.00 for a drink.

5 0

3 years ago