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2 years ago

Is the ordered pair (3, 0) a solution to 2x−5y=6 ?

Mathematics

2 answers:

erastova [34]2 years ago

4 0

Answer:

yes

Step-by-step explanation:

2x−5y=6

Substitute x=3 y=0 into the equation and see if it is true

2(3) -5(0) =6

6 -0 = 6

6=6

This is true so (3,0) is a solution

Greeley [361]2 years ago

3 0

Answer:

Yes (3, 0) is a solution.

Step-by-step explanation:

From the equation;

2x - 5y = 6

(x, y) = (3, 0)

3 and 0 equals x and y respectively

To test if the ordered pair is a solution to the equation, we would input the respective value of x and y;

2x - 5y = 6

2(3) - 5(0) = 6

6 - 0 = 6

6 = 6 (proof).

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Triangle A″B″C″ is formed by a reflection over x = 1 and dilation by a scale factor of 2 from the origin. Which equation shows t

andrew-mc [135]

Answer:

segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13

Step-by-step explanation:

Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).

1. Reflection over x = 1 maps vertices A, B and C as follows

A(-3,3)→A'(5,3);
B(1,-3)→B'(1,3);
C(-3,-3)→C'(5,-3).

2. Dilation by a scale factor of 2 from the origin has the rule

(x,y)→(2x,2y)

So,

A'(5,3)→A''(10,6);
B'(1,3)→B''(2,6);
C'(5,-3)→C''(10,-6)

See attached diagram for details

Note that

$A''B''=2AB\\ \\A''C''=2AC\\ \\B''C''=2BC,\\ \\AB=\sqrt{(-3-1)^2+(3-(-3))^2}=\sqrt{16+36}=\sqrt{52}=2\sqrt{13}$

$\dfrac{AB}{A''B''}=\dfrac{2\sqrt{13}}{2\cdot 2\sqrt{13}}=\dfrac{\sqrt{13}}{2\sqrt{13}}$

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3 years ago

If someone could help me figure out #7 ASAP I’d really appreciate it

IceJOKER [234]

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Good luck!

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2 years ago

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ElenaW [278]

Answer:

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Step-by-step explanation:

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Now we can calculate the numerators and keep the denominators the same.

$\frac{9}{6}$ x = 36

Find x.

$\frac{6}{6}$ x = $\frac{6}{9}$ × 36

x = 24

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2 years ago