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2 years ago

Find the mean of 1,0,10,7,13,2,9,15,0,3

Mathematics

2 answers:

svet-max [94.6K]2 years ago

8 0

1,0,10,7,13,2,9,15,0,3/ 10
=60/10
=6

Zarrin [17]2 years ago

5 0

Answer:

Step-by-step explanation:

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uppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.5

Marizza181 [45]

Answer:

$P(x \le 3.24) = 0.97725$

Step-by-step explanation:

Given

$\bar x = 2.5$

$\sigma = 0.37$

Required

Percentage that is not more than 3.24

The above implies that:

$x = 3.24$

Calculate z score

$z = \frac{x - \bar x}{\sigma}$

$z = \frac{3.24 - 2.5}{0.37}$

$z = \frac{0.74}{0.37}$

$z = 2$

So, the probability is represented s:

$P(x \le 3.24) = P(z \le 2)$

From z probability

$P(z \le 2) = 0.97725$

Hence:

$P(x \le 3.24) = 0.97725$

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2 years ago

I NEED HELP NOW ON PROBABILITY PART 3!!!!

inn [45]

22. P(n > 3) = P(4)+P(5) = (4+5)/30 = 9/30 = 3/10

23. The game isn't fair because there as many even numbers as there are odd numbers on a die. You get double the points he gets at the same chance!

6 0

2 years ago

Read 2 more answers

Which of the following is the function T(a) if T^-1(a)=11a-2

SpyIntel [72]

Answer:

T(a) =(a+2)/11

Step-by-step explanation:

The inverse of the inverse is the function

To find the inverse let T^-1(a) be y

y = 11a -2

Exchange y and a

a = 11y -2

Solve for y

Add 2 to each side

a+2 = 11y -2 +2

a+2 =11y

Divide each side by 11

(a+2)/11 =y

T(a) =(a+2)/11

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3 years ago

The arrival of customers at a service desk follows a Poisson distribution. If they arrive at a rate of two every five minutes, w

vampirchik [111]

Answer:

13.53% probability that no customers arrive in a five-minute period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

They arrive at a rate of two every five minutes

This means that $\mu = 2$

What is the probability that no customers arrive in a five-minute period?

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

13.53% probability that no customers arrive in a five-minute period

5 0

2 years ago

Help plzzz plzzz asappp!!!!

Svet_ta [14]

Answer:

α = 27.9794744° ≈ 28.0 m (nearest tenth)

Step-by-step explanation:

Step 1:

Opposite (O) = 42.5 (the side opposite to the reference angle, α)

Adjacent (A) = 80

Hypotenuse (H) = the longest side opposite to the right angle

2. We are given the adjacent (A) and opposite (O) lengths, we would use TOA. Which is:

Tan α = Opp/Adj

Plug in the values

Tan α = 42.5/80

3. Make α stand alone

α = $tan^{-1}(\frac{42.5}{80})$

4. α = 27.9794744° ≈ 28.0 m (nearest tenth)

8 0

2 years ago