Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
Plug all the point into your calculator. Not sure if you need it y=mx+b but the R for that is r= -1
Answer:
4 mile= 40
12 mile= 120
it will take him 80
Step-by-step explanation:
Let's use the slope-intercept equation:
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d)
Ok, so here your being asked to solve 6x2<span> + 5x = -7
The procedure that I did was using this formula it led me to get the following:
</span>Using the formula:
x = -(-5) ± √(-5)² - 4(6)(-6)/ 2(6)
x = 5 ± √ 25 + 144 / 12
x = 5 ± √ 169 / 12
x = 5 ± 13/12
x1 = 5 + 13/12
x1 = 18/12
x1 = 3/2
x2 = 5 - 13/12
x2 = -8/12
<span>
x2 = - 2/3
Hope this helped :)</span>
